x^2=2(2+30)

Solution for x^2=2(2+30) equation:

x^2=2(2+30)

We move all terms to the left:

x^2-(2(2+30))=0

We add all the numbers together, and all the variables

x^2-(232)=0

We add all the numbers together, and all the variables

x^2-232=0

a = 1; b = 0; c = -232;
Δ = b2-4ac
Δ = 02-4·1·(-232)
Δ = 928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{928}=\sqrt{16*58}=\sqrt{16}*\sqrt{58}=4\sqrt{58}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{58}}{2*1}=\frac{0-4\sqrt{58}}{2}
=-\frac{4\sqrt{58}}{2}
=-2\sqrt{58}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{58}}{2*1}=\frac{0+4\sqrt{58}}{2}
=\frac{4\sqrt{58}}{2}
=2\sqrt{58}
$